PHYICAL
posted by zzozo .
A small closed bottle is filled with water to adepth of 30 cm .A small hole located 10 cm above the bottom of the bottle is then opened .What is the speed of the water emerge from the hole in m\sex unit

(1/2) m v^2 = m g h
v = sqrt (2 g h) where h = 20 cm = .20 m 
The speed of the water will be in m/s units, not m/sex

h=0.30 m, hₒ=0.10 m.
Bernoulli’s equation between the top surface and the exitting stream:
Pₒ+0+ρghₒ=Pₒ+ρv²/2+ ρgh,
v² = 2g(hₒh),
v=sqrt{2g(hₒh)}=sqrt{2•9.8•(0.300.10)} =...