geometry
posted by angela .
Construct a truth table for (qvp)__> ~q

The truth table for ~q is the opposite:
q ~q
T F
F T
The truth table for conditional, p→q is true except when p is true and q is false, i.e.
p q p→q
T T T
T F F
F T T
F F T
For p∧q, the result is true only if both are true, i.e.
p q p∧q
T T T
T F F
F T F
F F F
Based on the above, you should attempt the compound truth table. Post if you have questions or need to verify your result. 
Sorry, I gave the truth table for ∧ when it should be or, ∨, which is false only when both p and q are false, i.e.
p q p∨q
T T T
T F T
F T T
F F F
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