A string is wrapped around a pulley of radius .20m and momentum of inertia .40 kg•m^2. The string is pulled with a force of 28 N. what is the magnitude of the resulting angular acceleration?
Can someone please go through the steps or at least guide me through them. I missed a few days in class and am trying to figure this out without any notes on it or anything.
force*radius=torque=momentinertia*angularacceleration
angular acceleration=force*radius/momentI
To find the magnitude of the resulting angular acceleration, we can use the equation:
Torque = Moment of inertia * Angular acceleration
The torque can be calculated using the following equation:
Torque = Force * Radius
In this case, the force is 28 N and the radius is 0.20 m. So we can substitute these values into the equation:
Torque = 28 N * 0.20 m
Next, we can substitute the value for torque into the first equation to solve for angular acceleration:
28 N * 0.20 m = 0.40 kg·m^2 * Angular acceleration
Now, solving for Angular acceleration:
Angular acceleration = (28 N * 0.20 m) / 0.40 kg·m^2
Angular acceleration = 14 N·m / 0.40 kg·m^2
Finally, we can calculate the value of angular acceleration:
Angular acceleration = 35 N·m / kg·m^2
Therefore, the magnitude of the resulting angular acceleration is 35 N·m / kg·m^2.