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A metal, M, of atomic mass 91 amu reacts with fluorine to form a salt that can be represented as MFx. In order to determine x and therefore the formula of the salt, a boiling point elevation experiment is performed. A 9.05-g sample of the salt is dissolved in 100.0 g of water and the boiling point of the solution is found to be 374.54 K. Find the formula of the salt. Assume complete dissociation of the salt in solution.


  • CHEM -

    Formula is MFx so molar mass is 91+19x
    delta T = i*Kb*m and
    m = mols/kg solvent and
    mols = g/molar mass
    374.54-273.15 = 1.39 = delta T.
    mols 9.05/molar mass
    m = 9.05/(91+19x)/0.1
    i = 1 for M + x for F
    Solve for x. My answer comes out 3.955 which rounds to 4 so I would think MF4 is the formula and the molar mass is 167. Check my work carefully because I don't see a metal that fits this MF4 category.

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