Math

posted by .

Why is the asymptote of the function in Example #1 y=2 ? ( y = 4x+3 + 2 )

  • Math -

    the question is not complete..
    linear functions do not have asymptote...

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. math

    There is a vertical asymptote at x=2, and a horizontal asymptote at y=3. Construct a suitable rational function f(x).
  2. Math

    Use the following information to construct a suitable rational function f(x). * There is a vertical asymptote at x=2, and a horizontal asymptote at y=3. * The graph of the function must go through the points (-4/3,0) and (0,-2)
  3. Precalculus

    Write an equation for rational function with given properties. a) a hole at x = 1 b) a vertical asymptote anywhere and a horizontal asymptote along the x-axis c) a hole at x = -2 and a vertical asymptote at x = 1 d) a vertical asymptote …
  4. math help!!

    Suppose a function, f(x) has a vertical asymptote toward positive infinity at x= -1, A horizontal asymptote at y = 1=2 as x ¨}‡1, and a turning point at (1;-1). Sketch what you think the function would look like.
  5. College Algebra

    3x-1/x^2-10x+26 Find all (real) zeros of the function Find all (real) poles of the function The function has... A horizontal asymptote at 0?
  6. college algebra

    Given the following rational function, find a. the horizontal asymptote(s), b. the vertical asymptote(s), if any, and c. the oblique asymptote(s), if any. f(x)=(x^2-x-2)/(2x^2-x-10)
  7. pre calculus

    use the seven step method to graph the following rational function: f(x)=3x^2+x-4/2x^2-5x a. determine the symmetry of the function. b. find the x and y intercepts. c. find the verticle asymptote d.find the horizontal asymptote e.plot …
  8. math

    Give an example of a rational function that has no horizontal asymptote and a vertical asymptote at x = 1.
  9. Math

    What is the: - vertical asymptote -horizontal asymptote -non permissible value of y=(x^2+x-12)/(x+4) ?
  10. Math (Integrals)

    The area A between the graph of the function: g(t) = 4 - (4/t^2) and the t-axis over the interval [1, x] is: A(x) = ∫[1, x] (4 - (4/t^2)) dt a) Find the horizontal asymptote of the graph g. I believe the horizontal asymptote of graph …

More Similar Questions