Given:
Ti=298K
V=.005 L
Pt=1 atm
P H20 vapor= .0313atm
P air= .9687 atm
you increase the temperature to 338K; the total pressure remains 1 atm, but the volume increases. Determine the volume at the new temperature (assume water vapor reaches equilibrium at 338K)
PLEASE help!! i've been attempting this problem for hours with no luck :(