Questions LLC
Login
or
Sign Up
Ask a New Question
Physics
Kinematics
Uniform Acceleration
A bus starts frm rest and moves with a uniform acceleration of (1m/secondsquare) for 5 minutes. calculate the velocity and distance??
1 answer
change 5 min to seconds.
distance=Vi*t+1/2 a t^2
vf=Vi+at
You can
ask a new question
or
answer this question
.
Related Questions
A car starts from rest and travels for 5.0 s with a uniform acceleration of + 1.5 m/s2. The driver then applies the brakes,
A car initially at rest travels for 2 minutes with a uniform acceleration of 0.3 m/s^2,after which the speed is kept constant
A car starts from rest and moves with constant acceleration during the 5th second of its motion,it covers a distance of 36
A car starts from rest accelerate uniformly until it reaches a velocity of 30m/s after 5s.it traves with uniform velocity for
If a car starts from rest and travels for 5.0 seconds with a uniform acceleration of +1.5 m/s2. The driver then applies the
A car starts from rest and travels for 5.3 s with a uniform acceleration of +1.2 m/s2. The driver then applies the brakes,
A car starts from rest and travels for 5.0 s with a uniform acceleration of +2.5 m/s2. The driver then applies the brakes,
A car starts from rest and travels for 5.10 s with a uniform acceleration of +1.40 m/s2. The driver then applies the brakes,
a particle starts from rest at o and moves in a straight line so that t seconds after, its velocity vm/s is given by v=2t-t^2.
A bus moves from rest with a uniform acceleration of 2m/s(square) for the first 10s. It then accelerate at a uniform rate of