If one mole of hydrocarbon contain 4g of hydrogen and it molar mass is 40g.what is the homologous series of the compound
%H = (4/40)*100 = 10%
%C = 100-10 = 90%.
Take 100 g sample which gives you
10g H and 90 g C.
mols C = 90/12 = about 7.5
mols H = 10/1 = about 10
Find the ratio of the elements to each other.
The easy way to do that is to divide both numbers by the smaller number.
C = 7.5/7.5 = 1.00
H = 10/7.5 = 1.33
To obtan whole numbers, multiply both by 3 to give C = 3 and H = 4
C3H4 is the molecular formula. Does that equal molar mass of 40? Yes (36+4=40).
The homologous series then is CnHn+1
Nice Work🤍
Oh, it sounds like we're talking about some smart little hydrocarbon! With 4g of hydrogen and a molar mass of 40g, it seems like we have a lovely compound from the alkene homologous series. It's like a fancy sibling group where all the members share similar characteristics and properties but have different numbers of carbon atoms. Keep up the good work, Mr./Ms. Smarty Pants!
To determine the homologous series of a compound, we need to consider the functional group present in the compound. The molar mass of the hydrocarbon is given as 40 g and it contains 4 g of hydrogen.
The molar mass of the hydrocarbon is equal to the sum of the molar masses of its constituents. In this case, since only hydrogen is mentioned, the hydrocarbon is made up of 4 g of hydrogen atoms.
The molar mass of hydrogen is approximately 1 g/mol. Therefore, the number of moles of hydrogen in the hydrocarbon is given by:
moles of hydrogen = mass of hydrogen / molar mass of hydrogen = 4 g / 1 g/mol = 4 mol
Since the hydrocarbon contains 4 moles of hydrogen, it must also contain 4 carbons since the hydrogen-carbon ratio for hydrocarbons is usually 1:1.
Therefore, the formula for the hydrocarbon is C4H4.
Now, let's determine the homologous series based on the formula C4H4.
The formula C4H4 suggests that the hydrocarbon is an unsaturated hydrocarbon with a carbon-carbon double bond. One possible homologous series for this hydrocarbon is the series of alkenes.
Thus, the homologous series of the compound with the formula C4H4 is the alkene series.
To determine the homologous series of a hydrocarbon, we need to consider its molecular formula and structure. However, with the given information, we can make some assumptions to figure out the potential homologous series.
First, let's look at the ratio of hydrogen to carbon in the compound. Since one mole of hydrocarbon contains 4 grams of hydrogen, and hydrogen has a molar mass of 1 gram/mole, we can infer that the hydrocarbon has 4 moles of hydrogen.
Next, we know the molar mass of the hydrocarbon is 40 grams, implying that the total molar mass of carbon in the molecule is 40 grams - (4 grams of hydrogen x 1 gram/mole) = 36 grams. As the molar mass of carbon is 12 grams/mole, we can calculate that there are 36 grams / (12 grams/mole) = 3 moles of carbon.
Now, let's analyze the ratio of carbon to hydrogen in the hydrocarbon. We have 3 moles of carbon and 4 moles of hydrogen, which can be simplified to a ratio of 1:4.
Based on this ratio, we can infer that the hydrocarbon belongs to the homologous series of alkanes. In alkanes, each carbon atom forms four bonds (either with other carbon atoms or hydrogen atoms), resulting in the ratio of carbon to hydrogen of 1:4.
Therefore, the homologous series of the compound would be alkanes.