Post a New Question


posted by .

In the early 1960s, radioactive strontium-90 was released during atmospheric testing of nuclear weapons and got into the bones of people alive at the time. If the half-life of strontium-90 is 27 years, what fraction of the strontium-90 absorbed in 1962 remained in people's bones in 1994?

  • calculus -

    1994-1962 = 32 years

    A = Ao*2^-t/27, so
    A/Ao = 2^-32/27 = .4397 = 43.97%

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question