A man (80kg) jumps from a 17 storey balcony (51 metres). How long would it take for him reach the ground?
~Sorry for the morbid example, we were just having a chat about it lol
h+g*t^2/2
t=sqrt(2h/g)
=sqrt(2*51/9.8)
= 3.2 sec
Assuming air resistance is negligible.
To calculate the time it takes for a person to reach the ground after jumping from a certain height, we can use the equation of motion known as the free fall equation.
The free fall equation is given by:
d = (1/2) * g * t^2
Where:
- d is the distance fallen (in meters)
- g is the acceleration due to gravity (which is approximately 9.8 m/s^2)
- t is the time taken (in seconds)
In this case, the distance fallen (d) is 51 meters, as the man jumps from a 17-story balcony (assuming each story is approximately 3 meters).
Plugging in the values into the equation, we get:
51 = (1/2) * 9.8 * t^2
Simplifying the equation:
51 = 4.9 * t^2
Dividing both sides of the equation by 4.9:
t^2 = 51 / 4.9
t^2 ≈ 10.41
To find the value of t (time), we take the square root of both sides:
t ≈ √10.41
t ≈ 3.2 seconds
Therefore, it would take approximately 3.2 seconds for the man to reach the ground after jumping from the 17-storey balcony.