posted by Jezrell
Please answer asap with complete solution thanks a lot. I need the solution to answer other questions much alike to this one. :)
Two electrons are 10^-15 meters apart. One electron is fixed on its position. The other, originally at rest, is released. How fast is the free electron moving when it is 10^-3 in from the fixed charge. (Solve using the Law of Conservation of Energy)
Assume the fixed electron is at zero PE, zero KE.
Then the PE of the original electron is -ke^2/1E-15
at the new position, energy is conserved, so new PE+KE=original PE
-ke^2/1E-15=-ke^2/1E-3 + KE
find KE, then KE= 1/2 m v^2