physics
posted by Jezrell .
Please answer asap with complete solution thanks a lot. I need the solution to answer other questions much alike to this one. :)
Two electrons are 10^15 meters apart. One electron is fixed on its position. The other, originally at rest, is released. How fast is the free electron moving when it is 10^3 in from the fixed charge. (Solve using the Law of Conservation of Energy)

Assume the fixed electron is at zero PE, zero KE.
Then the PE of the original electron is ke^2/1E15
at the new position, energy is conserved, so new PE+KE=original PE
ke^2/1E15=ke^2/1E3 + KE
find KE, then KE= 1/2 m v^2