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A 1370 kg car rolling on a horizontal surface has a speed of 20 km/hr when it strikes a horizontal coiled spring and is brought to rest in a distance of 5.5 m. What is the spring constant (in N/m) of the spring? (Ignore nonconservative forces such as friction.)

  • physics -

    Loss in KE = Gain in elastic PE of the spring.
    (1/2)mV^2 = (1/2)kx^2
    find K from this equation. Remember to convert the units of V to m/s

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