A 20 N force acts on a 10 kg object parallel to the object's displacement. If the force acts for 32 m, what is the final kinetic energy, in J, of the object assuming it starts from rest?

a=F/m = 20/10=2 m/s².

s=(v²-vₒ²)/2a.
vₒ=0
v²= 2as.
KE=mv²/2= m2as/2=mas=10•2•32=640 J

To find the final kinetic energy of the object, we need to first calculate the work done on the object and then use that to determine the change in kinetic energy.

The work done on an object is given by the formula: Work = force × displacement × cos(theta), where theta is the angle between the force and displacement vectors. In this case, the angle theta is 0 degrees because the force is acting parallel to the object's displacement.

Given:
Force (F) = 20 N
Displacement (d) = 32 m
Mass (m) = 10 kg

To calculate the work done, we can use the formula:
Work = F × d × cos(0)

Since cos(0) is equal to 1, we can simplify the formula to:
Work = F × d

Substituting the given values, we get:
Work = 20 N × 32 m = 640 N·m

Now, the work done is equal to the change in kinetic energy of the object. So, we can write:
Work = ΔKE

The initial kinetic energy of the object is 0 J because it starts from rest. Therefore, the final kinetic energy (ΔKE) is equal to the work done.

Hence, the final kinetic energy of the object is 640 J.