find the center and radius of (x+8)2 + (y+4)2 =49
standard equation for a circle of radius r with center at (h,k) is
(x-h)^2 + (y-k)^2 = r^2
look at your equation and just read 'em off.
To find the center and radius of a circle, we can use the equation of a circle in the standard form, which is (x-h)^2 + (y-k)^2 = r^2.
Comparing this standard form to the equation you provided, (x+8)^2 + (y+4)^2 = 49, we can see that the center of the circle is represented by the values (-h, -k) and the square root of the value on the right side of the equation, r.
In this case, the values of h and k in the equation (x+8)^2 + (y+4)^2 = 49 are -8 and -4 respectively.
Therefore, the center of the circle is located at the point (-8, -4) and the radius is the square root of 49, which is 7.
Hence, the center of the circle is (-8, -4) and the radius is 7.