# precalculus

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sinθ=12/13, θ lies in quadrant II. Find the exact value of sin2θ, cos 2θ, tan2θ

• precalculus -

5 , 12, 13 right triangle
sin T = 12/13
cos T = -5/13
tan T = -12/5
use identities to get functions of the angle doubled
eg
sin 2T = 2 sin T cos T = 2(12/13)(-5/13)

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