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precalculus

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sinθ=12/13, θ lies in quadrant II. Find the exact value of sin2θ, cos 2θ, tan2θ

  • precalculus -

    5 , 12, 13 right triangle
    sin T = 12/13
    cos T = -5/13
    tan T = -12/5
    use identities to get functions of the angle doubled
    eg
    sin 2T = 2 sin T cos T = 2(12/13)(-5/13)

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