3h2+n2 makes 2NH3's if I have 4
moles of H2 instead and 2 moles of N2
would I still just say I have 2.0 or 2.7?
You do these with a factor. The right factor will convert anything to anything. Here is how you do this one. But I caution you to use caps when required. h2 and n2 don't mean anything to anyone. Also note that you have asked a limiting reagent question. I know that because you have listed quantities for BOTH reactants.
3H2 + N2 ==> 2NH3
First, how much NH3 can be produced with 4 mols H2 and all of the N2 we need?
4 mols H2 x (2 mol NH3/3 mol H2) = 4 x (2/3) = 8/3 = 2.67 mol NH3.
Next, how much NH3 can be produced with 2 mols N2 and all of the H2 we need?
2 mols N2 x (2 mol NH3/1 mol N2) = 2 x (2/1) = 4 mol NH3.
So which number is right? 2.67 or 4 mol NH3. The correct answer in limiting reagent problems is ALWAYS the smaller one. So 2.67 mols NH3 will be produced if we react 4 mols H2 and 2 mols N2.
4mols H2 x (