posted by Aaron .
3.30 mL of vinegar needs 40.0 mL of 0.150M NaOH to reach the equivalence point in a titration, how many grams of acetic acid are in a 1.10 qt sample of this vinegar?
mols NaOH = M x L = 0.150 x 0.0400 = ?
mols acetic acid = same as mols NaOH.
That gives you mols acetic acid in 3.30 mL. That times molar mass acetic acid gives you grams acetic acid in 3.30 mL.
g acetic acid in 3.30 mL x (mL in 1 qt/3.30) = ?