Two forces, 1 and 2, act on the 5.00 kg block shown in the drawing. The magnitudes of the forces are F1 = 58.0 N and F2 = 26.5 N. What is the horizontal acceleration (magnitude and direction) of the block?
add the forces as vectors, then
net force= mass*acceleration
To find the horizontal acceleration of the block, we can use Newton's second law of motion, which states that the net force on an object is equal to the mass of the object multiplied by its acceleration.
First, let's find the net horizontal force acting on the block. Since the block is being acted upon by two forces (F1 and F2) in the horizontal direction, the net force can be calculated by taking the difference between the two forces.
Net Force = F1 - F2
Substituting the given values:
Net Force = 58.0 N - 26.5 N
Net Force = 31.5 N
Next, we can use Newton's second law to solve for the acceleration. Rearranging the equation, we have:
Acceleration = Net Force / Mass
Substituting the values:
Acceleration = 31.5 N / 5.00 kg
Acceleration = 6.3 m/s^2
Therefore, the magnitude of the horizontal acceleration of the block is 6.3 m/s^2. The direction of the acceleration will be in the same direction as the net force, which is not specified in the question.