algebra
posted by Anonymous .
How much bigger is the area of a square with side 3x + 2y inches than a square with side 2x  y inches?

Area of square with side 3x+2y
= (3x+2y)^2
= 9x^2 + 12xy + 4y^2
area of square with side 3x2y
= (3x2y)^2
= 9x^2  12xy + 4y^2
difference = 24xy