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algebra

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How much bigger is the area of a square with side 3x + 2y inches than a square with side 2x - y inches?

  • algebra -

    Area of square with side 3x+2y
    = (3x+2y)^2
    = 9x^2 + 12xy + 4y^2

    area of square with side 3x-2y
    = (3x-2y)^2
    = 9x^2 - 12xy + 4y^2

    difference = 24xy

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