algebra 1
posted by Anonymous .
Solve this system using elimination. If a single solution exists, write the solution as an ordered pair. Your answer will be an ordered pair, no solution, or infinitely many solutions.
5x=y=15
3x+2y=9

assuming you mean
5x+y=15
3x+2y=9
multiply the first by 2:
10x + 2y = 30
3x + 2y = 9
now subtract:
7x = 21
x = 3
so, y = 0
solution: (3,0)
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