Post a New Question

chemistry

posted by .

What is the molarity of a saline solution that contains 0.900 g NaCl (58.44 g/mol) dissolved in 100.0 ml of a solution?

  • chemistry -

    M = moles/L soln
    mols = grams/molar mass
    L soln = 0.1L.

  • chemistry -

    [.900 g NaCl (1 mole / 58.44 g)] / [100.0 mL (1L/1000mL) =

    [(.900 mole NaCl) / 58.44g] / (0.1L) = 0.15 mole/L NaCl --> 0.15M solution

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question