# chemistry

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What is the molarity of a saline solution that contains 0.900 g NaCl (58.44 g/mol) dissolved in 100.0 ml of a solution?

• chemistry -

M = moles/L soln
mols = grams/molar mass
L soln = 0.1L.

• chemistry -

[.900 g NaCl (1 mole / 58.44 g)] / [100.0 mL (1L/1000mL) =

[(.900 mole NaCl) / 58.44g] / (0.1L) = 0.15 mole/L NaCl --> 0.15M solution

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