What is the molarity of a saline solution that contains 0.900 g NaCl (58.44 g/mol) dissolved in 100.0 ml of a solution?
[.900 g NaCl (1 mole / 58.44 g)] / [100.0 mL (1L/1000mL) =
[(.900 mole NaCl) / 58.44g] / (0.1L) = 0.15 mole/L NaCl --> 0.15M solution
To find the molarity of a solution, we need to calculate the number of moles of solute (NaCl) and divide it by the volume of the solution (in liters).
Step 1: Calculate the number of moles of NaCl.
Number of moles = mass of NaCl / molar mass of NaCl
Given:
Mass of NaCl = 0.900 g
Molar mass of NaCl = 58.44 g/mol
Number of moles = 0.900 g / 58.44 g/mol
Number of moles = 0.0154 mol
Step 2: Convert the volume of the solution from milliliters to liters.
Volume of solution = 100.0 ml = 100.0 / 1000 = 0.100 L
Step 3: Calculate the molarity.
Molarity = Number of moles / Volume of solution
Molarity = 0.0154 mol / 0.100 L
Molarity = 0.154 M
Therefore, the molarity of the saline solution is 0.154 M.
To find the molarity of a solution, we need to calculate the number of moles of solute (NaCl) and then divide it by the volume of the solution in liters.
Step 1: Calculate the number of moles of NaCl.
The molar mass of NaCl is 58.44 g/mol. We have 0.900 g of NaCl.
moles = mass / molar mass
moles = 0.900 g / 58.44 g/mol
moles = 0.0154 mol
Step 2: Convert the volume of the solution to liters.
We have 100.0 mL of the solution, which is equal to 0.100 L.
Step 3: Calculate the molarity.
Molarity (M) = moles of solute / volume of solution in liters
Molarity = 0.0154 mol / 0.100 L
Molarity = 0.154 M
Therefore, the molarity of the saline solution is 0.154 M.
M = moles/L soln
mols = grams/molar mass
L soln = 0.1L.