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algebra

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I do not know where to start with this one. Suppose p varies directly as the square of z and inversely as r. If p = 32/5 when z = 4 and r = 10, find p when z = 3 and r = 36.

  • algebra -

    " p varies directly as the square of z and inversely as r "
    ----> p = k (√z) (1/r) , where k is a constant

    given: p=32/5 , z=4, r=10
    32/5 = k(√4)(1/10)
    times 10
    64 = 2k
    k = 32

    so p = 32√z/r

    then when z=3,r=36
    p = 32√3/36
    = 8√3/9 or appr 1.54

  • algebra -

    6x+4(70-x)=300

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