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A 0.22 calibre rifle shoots a bullet of mass 1.8 g with a muzzle velocity of 500 m/s. If the barrel is 25 cm long, what is the average force exerted on the bullet while it is in the barrel?

  • Physics -

    force * distance = work
    so work done = .025 F
    which we assume is Ke of bullet
    (1/2) m v^2 = .025 F
    (1/2) (.0018) (500)^2 = .025 F

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