Physics
posted by Sarah .
A bomb is dropped from a plane flying at 4000 meters. The plane is flying at 80 m/s. How far, in a horizontal direction, did the bomb hit the ground?

S=(1/2)gt^2 since u=0
4000=(1/2)*10*t^2
t=sqrt(800)secs  time to reach ground
So hor. distance covered= 80*sqrt(800)
= 2263m 
h = ho  o.5g*t^2 = 0
4000  4.9t^2 = 0
4.9t^2 = 4000
t^2 = 816.3
Tf = 28.6 s. = Fall time or time in flight.
Dx = Hor = 80m/s * 28.6s = 2286 m.
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