Physics

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A bomb is dropped from a plane flying at 4000 meters. The plane is flying at 80 m/s. How far, in a horizontal direction, did the bomb hit the ground?

  • Physics -

    S=(1/2)gt^2 since u=0
    4000=(1/2)*10*t^2
    t=sqrt(800)secs - time to reach ground
    So hor. distance covered= 80*sqrt(800)
    = 2263m

  • Physics -

    h = ho - o.5g*t^2 = 0
    4000 - 4.9t^2 = 0
    -4.9t^2 = -4000
    t^2 = 816.3
    Tf = 28.6 s. = Fall time or time in flight.

    Dx = Hor = 80m/s * 28.6s = 2286 m.

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