A lead ball has a volume of 94.3 cm3 at 19.3°C. What is the change in volume when its temperature changes to 34.3°C?

94.4cm3 was the answer I put and I was wrong. Can someone help?

How can you get the same volume?

Show me your work.

To determine the change in volume when the temperature changes, you need to consider the thermal expansion of the lead ball. The equation that relates the change in volume to the change in temperature is given by:

ΔV = V * α * ΔT

Where:
ΔV is the change in volume
V is the initial volume of the lead ball
α is the coefficient of linear expansion for lead (which measures how much a material expands or contracts when the temperature changes)
ΔT is the change in temperature

To find the answer, you need to know the coefficient of linear expansion for lead. The coefficient of linear expansion for most materials can be found in reference tables, or you can perform an internet search.

Let's assume that the coefficient of linear expansion for lead (α) is 0.000029 (1/°C).

Based on the given information:
Initial volume (V) = 94.3 cm3
Initial temperature (T1) = 19.3°C
Final temperature (T2) = 34.3°C

To calculate the change in volume (ΔV), you can use the equation:

ΔV = V * α * ΔT

First, calculate the change in temperature:

ΔT = T2 - T1
= 34.3°C - 19.3°C
= 15°C

Now plug in the values:

ΔV = 94.3 cm3 * (0.000029 (1/°C)) * 15°C

ΔV ≈ 0.0409 cm3

Therefore, the change in volume when the temperature changes from 19.3°C to 34.3°C is approximately 0.0409 cm3.

Note: The given answer of 94.4 cm3 is incorrect because it does not take into account the change in temperature and the coefficient of linear expansion of lead.