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find the slope of the tangent line to y^4 = 3x^2 - 2x at the point (1,1)

4y^3 y' = 6x-2
y' = (6x-2)/(4y^3)

at (1,1) y' = 4/4 = 1

line is thus (y-1) = 1(x-1)
y = x

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