hi i need help differentiating these..
1. y = cos(3x^2 + 2x)
2. y = ln(3x^2 + 5)
thank you
use the old chain rule:
y = cos(u)
y' = -sin(u) u' = -sin(3x^2+2x)(6x+2)
y = ln(u)
y' = 1/u u' = 1/(3x^2+5) * 6x = 6x/(3x^2+5)
1. y = cos(3x^2 + 2x)
2. y = ln(3x^2 + 5)
thank you
y = cos(u)
y' = -sin(u) u' = -sin(3x^2+2x)(6x+2)
y = ln(u)
y' = 1/u u' = 1/(3x^2+5) * 6x = 6x/(3x^2+5)