a 230.0ml sample of a 0.275 molarity solution is left on a hot plate over night the folowing morning the solution is 1.5 molarity. what volume of solvent has evaportated from the 0.275 molarity solution?
See above.
To calculate the volume of solvent that has evaporated from the 0.275 molarity solution, we need to use the formula:
M₁V₁ = M₂V₂
Where:
M₁ = initial molarity of the solution
V₁ = initial volume of the solution
M₂ = final molarity of the solution
V₂ = final volume of the solution
Given:
M₁ = 0.275 M (initial molarity)
V₁ = 230.0 mL (initial volume)
M₂ = 1.5 M (final molarity)
We need to find V₂ (final volume), which represents the volume of solvent remaining after evaporation. Let's rearrange the formula to solve for V₂:
V₂ = (M₁V₁) / M₂
Substituting the given values:
V₂ = (0.275 M) * (230.0 mL) / (1.5 M)
Now, let's calculate:
V₂ = 0.275 * 230.0 / 1.5
V₂ ≈ 42.67 mL
Therefore, approximately 42.67 mL of the solvent has evaporated from the 0.275 Molarity solution.