A box contains 25 slips of paper, numbered 1 to 25. What is the probability that one will randomly select a number that is divisible by 3 or 7?
3, 6, 9, 12, 15, 18, 21, 24
7, 14, 21
That looks like 10/25 or 2/5.
Ah, probability, my favorite topic to clown around with! Alright, let's solve this math puzzle.
First, let's figure out how many numbers between 1 and 25 are divisible by 3. We have 3, 6, 9, 12, 15, 18, 21, and 24. So that's a grand total of 8 numbers divisible by 3.
Now, let's see how many numbers are divisible by 7. We have 7, 14, 21, and that's it. So we have a total of 3 numbers divisible by 7.
But hold your laughter, we’re not done yet! If we just add up these numbers, we’ll be counting 21 twice since it’s divisible by both 3 and 7. So we need to subtract one occurrence of 21 from our total.
Thus, we have 8 + 3 - 1 = 10 numbers that are divisible by either 3 or 7.
Now, the total number of slips of paper in the box is 25. So the probability of randomly selecting a number that is divisible by 3 or 7 is 10/25.
Simplifying the fraction, we get a probability of 2/5, or as I like to say, a 40% chance of getting a number that will make your inner mathematician smile!
I hope that brings a bit of probability fun to your day!
To find the probability of selecting a number that is divisible by 3 or 7, we need to determine the number of favorable outcomes (numbers divisible by 3 or 7) and the total number of possible outcomes (numbers from 1 to 25).
Let's first calculate the number of favorable outcomes.
Numbers divisible by 3:
3, 6, 9, 12, 15, 18, 21, 24 (8 numbers)
Numbers divisible by 7:
7, 14, 21 (3 numbers)
There is one number, 21, which is divisible by both 3 and 7. We count it only once, so we have a total of 8 + 3 - 1 = 10 favorable outcomes.
Now, let's calculate the total number of possible outcomes, which is 25.
Therefore, the probability of selecting a number that is divisible by 3 or 7 is 10/25 or 2/5.
So, the probability is 2/5.
To find the probability of selecting a number that is divisible by 3 or 7, we need to count the number of favorable outcomes and the total number of possible outcomes.
First, let's determine the number of favorable outcomes. We need to count the number of numbers from 1 to 25 that are divisible by 3 or 7.
Numbers divisible by 3:
3, 6, 9, 12, 15, 18, 21, 24
Numbers divisible by 7:
7, 14, 21
We have a total of 11 numbers that are divisible by 3 or 7.
Next, let's count the total number of possible outcomes. In this case, the total number of slips of paper in the box is 25.
Therefore, the probability of selecting a number that is divisible by 3 or 7 is:
Number of favorable outcomes / Total number of possible outcomes = 11 / 25
Simplifying this fraction, we find that the probability is 11/25 or approximately 0.44 (or 44%).