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Physics(Please respond)

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A system does 210 J of work on its environment and gains 80.6 J of heat in the process. Find the change in the internal energy of (a) the system and (b) the environment.

I am not sure how to start this.

  • Physics(Please respond) -

    ΔU = Q - W
    Where ΔU is the change in the internal energy of the system,
    Q is the heat/energy gained from the surroundings,
    W is the work done on the environment.

    ΔU =80.6-210=-129.4 J.
    The internal energy decreased by 129.4 Joules which corresponds to a temperature decrease of the system

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