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If 200 of the adults surveyed were in the age category of 24 and under and they provided a standard deviation of \$14.50, construct a 95% confidence interval for the weekly average expenditure on fast food for adults 24 years of age and under. Assume fast food weekly expenditures are normally distributed.

• Statistics -

95% = mean ± 1.96 SEm

SEm = SD/√n

Do you know the mean?

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