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If a baseball is projected upward from ground level with an initial velocity of 64 feet per second, then its height is a function of time, give by g(t)= -16^2 + 64t. What is the maximum heigh reached by the ball?

  • Math -

    max height is when g is max

    I think you meant

    g(t)=-16t^2+64t

    g(t)=16t(4-t) or g=0 at t=0 and t=4

    so max height is at t=2, the mid point

    maxheight= -16*4+64*2=64meters

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