physical science
posted by lora .
a ball dropped off a cliff and took 3.59s to fall to the water below. neglecting air resistance how far in meters did it fall how far is it down to water

v=vₒg•t
at the top point
0= vₒg•t1,
t1= vₒ/g =34.7/9.8=3.54 s.
h= vₒ•t1 –g•t1²/2=34.7•3.54  9.8•3.54²/2 =61.5 m
h=g•t2²/2,
t2=sqrt(2•h/g) =
=sqrt(2•61.5 /9.8) = 3.54 s.
Time upward =time downward!
t =2•t1=2•3.54 =7.08 s.