Find the value of the derivative of y=sin^2(0.25x^4) at the point (ð,0.17)

1 answer

y' = 2sin(.25x^4)cos(.25x^4)(x^3)

= x^3 sin(.5x^4)

not sure what your angle is. Solving for x when y=0.17 didn't give me a useful value.

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Find the value of the derivative of y=sin^2(0.25x^4) at the point (ð,0.17)

y' = 2sin(.25x^4)*cos(.25x^4)*(x^3)

y' = 2sin(.25x^4)cos(.25x^4)(x^3)