An Object of mass 0.5kg is whirled at the end of string 0.8m long. If the strings makes three revolutions in 1.2sec, find the tension in the string.
98.00
98.2...N
98.2 n
To find the tension in the string, we can use the formula for centripetal force:
Tension = (mass x velocity^2) / radius
First, we need to find the velocity of the object. Since it make three revolutions in 1.2 seconds, we can calculate the angular velocity (ω) using the formula:
ω = (2π x number of revolutions) / time
ω = (2π x 3) / 1.2
= 15π / 6
Next, we can find the linear velocity (v) using the formula:
v = angular velocity x radius
v = (15π / 6) x 0.8
= 4π m/s
Now, we can calculate the tension in the string:
Tension = (mass x velocity^2) / radius
= (0.5 x (4π)^2) / 0.8
= (0.5 x 16π^2) / 0.8
= 32π^2 / 0.8
= 40π^2
Therefore, the tension in the string is 40π^2 Newtons.