Questions LLC
Login
or
Sign Up
Ask a New Question
Physics
Thermodynamics
Heat Transfer
what is the equilibrium temperature if 100 grams of water at 20 degrees celsius is added to 50 grams of water at 62 degrees celsius in an insulated container of negligible mass?
1 answer
100 (T-20) = 50 (62-T)
solve for T
You can
ask a new question
or
answer this question
.
Related Questions
A 100g sample of water at 90 degrees celsius is added to a 100g sample of water at 10 degrees celsius.
The final temperature of
2) To the solution in problem 1 (d) at 100 degrees celsius, 10g of water are added, and the solution is cooled to 0 degrees
A copper calorimeter weighs 100g when empty, 400g when half full of water at 0 degrees Celsius, and 450g when ice at 0 degree
Please Help!
An object at 20 degrees Celsius with heat capacity 100 calories/Celsius is placed in 40 grams of water at 100
An insulated beaker contains 300g of water initially at 30 degree celsius. water at 100 degree celsius is added until the
if 27 grams of ice at 0 degrees celsius is added to 123 grams of water at 100 degrees celsius in an insulated container,
A 5.0-g Sample of KBr at 25.0 degrees celsius dissolves in 25.0 degrees celsius 25.0 mL of water also at 25.0 degrees celsius.
if 8.100 grams of C6H6 is burned and heat is produced from the burning is added to 5691 grams of water at 21 degrees celsius
An unknown volume of water at 18.2 degrees celsius is added to 24.4 mL of water at 35.0 degrees celsius. If the final
A physicist converted 2kg of water at 37 degrees Celsius to steam at 100 degrees Celsius.
Assuming no heat is lost, calculate the