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An investment adviser invested $14,000 in two accounts. One investment earned 5% annual simple interest, and the other investment earned 2.5% annual simple interest. The amount of interest earned for 1 year was $540. How much was invested in each account?

  • Algebra -

    amount invested at 5% --- x
    amount invested at 2.5% --- 14000-x

    solve for x
    .05x + .025(14000-x) = 540

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