# Algebra

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An investment adviser invested \$14,000 in two accounts. One investment earned 5% annual simple interest, and the other investment earned 2.5% annual simple interest. The amount of interest earned for 1 year was \$540. How much was invested in each account?

• Algebra -

amount invested at 5% --- x
amount invested at 2.5% --- 14000-x

solve for x
.05x + .025(14000-x) = 540

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