Physics

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• Physics -

Volume of sphere =π•D³/6 = 4188.8 m³,
Surface of sphere = π•D² = 1256.6 m²,
Volume of lead foil = 1256.6•0.00025 = 0.314 m³
Mass of the lead foil = ρ•V= 11300•0.314 = 3548.2 kg.
(a) Weight = mg=[m(sph)+m(passenger)+m(He)] •g=
= [3548.2+295+749.8] •9.8=45011.4 N.
(b) 4188.8 m³,
(c) F= ρ•V•g=1.28•4188.8•9.8 = 52544.3 N.
(d) Δ= 52544.3-45011.4=7532.9 N
7532.9>7500 => This balloon can lift the payload.

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