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If a baseball is projected upward from ground level with an initial velocity of 64 feet per second, then its height is a function of time given y s(t) = -16t^2 + 64t. Graph this function for 0 < t<4, what is the maximum height?

  • Math -

    Tv = -B/2A = -64 / -32 = 2 s.
    Y = -16*2^2 + 64*2 = 64 Ft, = Max. ht.

    V(T,Y) = (2,64).

    Complete the chart below for graphing.
    (T,Y).
    (0.5,28)
    (1.0,48).
    (1.5,
    V(2.0,64).
    (2.5,
    (3.0,
    (3.5,

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