What is the concentration of a solution of lithium carbonate containing 0.01 mol in 750 mL of solution
What volume of 0.01 mol L-1 Li2CO3 solution would contain 0.035 mol lithium carbonate?
Give your answer as 2 sig fig (this is technically not correct), followed by a space then the units.
How many moles of lithium carbonate are contained in 400 mL of a lithium carbonate solution with a concentration of 0.015 mol L-1? Give your answer as two sig. figures, followed by a space and the units
What is the concentration, in mol L-1, of a solution containing 1.2 g of lithium carbonate in 100 mL solution?
Give your answer as 2 sig fig, followed by a space and the units (remember the units given in a previous question).
What is the concentration, in g/L, of a solution containing 0.65 mol HNO3 in 150 mL solution?
Give your answer rounded to nearest whole number, followed by a space and the units.
See your posts above.
To answer these questions, we need to use the formula for concentration, which is:
Concentration = (Amount of solute) / (Volume of solution)
1. For the first question, the amount of solute is given as 0.01 mol and the volume of solution is given as 750 mL. So, we can substitute these values into the formula:
Concentration = 0.01 mol / 750 mL
To get the answer, divide 0.01 by 750 and express the result with a suitable unit, such as mol/L (M). Remember to round to the appropriate number of significant figures.
2. For the second question, the amount of solute is given as 0.035 mol and the concentration is given as 0.01 mol L-1. We can rearrange the formula to find the volume of the solution:
Volume of solution = Amount of solute / Concentration
Substituting the given values:
Volume of solution = 0.035 mol / 0.01 mol L-1
Calculate this division to find the volume of the solution. Express the answer with two significant figures and the correct units.
3. For the third question, the volume of the solution is given as 400 mL and the concentration is given as 0.015 mol L-1. We can use the same formula as before to find the amount of solute:
Amount of solute = Concentration x Volume of solution
Plugging in the values:
Amount of solute = 0.015 mol L-1 x 400 mL
Calculate this multiplication to find the amount of solute.
4. For the fourth question, the mass of the solute is given as 1.2 g and the volume of the solution is given as 100 mL. We need to convert the mass to moles using the molar mass of Li2CO3 (lithium carbonate) which is 73.89 g/mol. Then we can use the same formula to find the concentration:
Amount of solute (in mol) = Mass of solute (in g) / Molar mass of Li2CO3
Concentration = Amount of solute / Volume of solution
Substituting the given values:
Amount of solute = 1.2 g / 73.89 g/mol
Concentration = (1.2 g / 73.89 g/mol) / 100 mL
Calculate these divisions to find the concentration. Express the answer with two significant figures and the correct units.
5. For the fifth question, the amount of solute is given as 0.65 mol and the volume of the solution is given as 150 mL. We can use the same formula to find the concentration:
Concentration = Amount of solute / Volume of solution
Substituting the given values:
Concentration = 0.65 mol / 150 mL
Calculate this division to find the concentration in mol/L. Round to the nearest whole number and express the answer with the correct units.