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physics

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An object falls from the top of the school, which is 6.06m high. Assume air resistance can be ignored and the acceleration is 9.8m/s^2
If the object was dropped( not thrown) , what is its speed after 0.333s

How long does it take to hit the ground

  • physics -

    v = at = -9.8(.333) = -3.26

    s = 6.06 - 4.9t^2
    when it hits, s=0, so
    0 = 6.06 - 4.9t^2
    t = 1.11

  • physics -

    The speed at t = 0.333 s is
    V = (g/2) t^2

    It hits the ground when (g/2) t^2 = 6.06 m

    Solve for that new t.

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