A 25 N book sits on a table. What is the magnitude of the normal force the table exerts on the book?
Hint: The acceleration of the book is zero. Therefore, the sum of all the forces that act on the book is zero.
Newton's 3 law:
For every action there is an equal and opposite reaction: ↑ N == mg↓
normal force N = mg = 25 N
The magnitude of the normal force the table exerts on the book is equal to the weight of the book, which is given as 25 N. Therefore, the magnitude of the normal force is also 25 N.
To find the magnitude of the normal force the table exerts on the book, we need to understand that the normal force is the force exerted by a surface to support the weight of an object resting on it. In other words, it is the force that prevents the object from sinking into or falling through the surface.
In this case, since the book is sitting on a table, the normal force is equal in magnitude and opposite in direction to the force of gravity acting on the book. The force of gravity can be calculated using the formula:
Force of gravity = mass × acceleration due to gravity
Since the weight of an object is equal to the force of gravity, we can calculate the weight using the formula:
Weight = mass × acceleration due to gravity
In this scenario, the weight of the book is given as 25 N, which represents the magnitude of the gravitational force acting on the book. Therefore, the magnitude of the normal force exerted by the table on the book is also 25 N in the opposite direction.
So, the magnitude of the normal force the table exerts on the book is 25 N.