probability
posted by Anonymous .
two dice are tossed. find the probability that the sum is odd given that the sum is 5 or less

A=sum is odd
B=sum is 5 or less
P(B)={(1,1),(1,2),(1,3),(1,4),(2,1),(2,2),(2,3),(3,1),(3,2),(4,1)}/36
=10/36
P(A∩B)={(1,1),(1,3),(2,1),(2,3),(3,2),(4,1)}/36
=6/36
P(AB)=P(A given B)
=P(A∩B)/P(B)
=?
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