Physics
posted by Jen .
Find the magnitude of the gravitational attraction force that the earth exerts on a 62kilogram astronaut who is 8.00 X 10^7 meters away from the center of the earth.
Useful numbers: M^earth=5.98 X 10^24kg; G=6.67 X 10^11 N*m^2kg^2
Please walk me through your steps, don't just suggest a formulathank you.

This is only one step  The Universal Law of Gravitation
F=G• m•M/(R)²
R= 8.00 X 10^7 m,
m=62 kg 
Question though, the answer in the book says that the answer is 3.9 Newtons...do I need to convert this answer or something?

F=G• m•M/(R)² =
=6.67•10^11•62•5.98•10^24/(8• 10^7)²=3.87 N ≈3.9 N 
Fabulous! Thank you!!!