Post a New Question

Physics

posted by .

A particle moved along the x axis with a constant acceleration of -85.0 meters per second squared. The initial position of the particle was at the origin and its initial velocity was +325 meters per second. Find the position of the particle at T=4.0 seconds.

Please walk through your steps,
Thank you very much.

  • Physics -

    v=vₒ-at.
    Assume v=0, than
    t= vₒ/a =325/85=3.82 s.
    It takes 3.82 s. to stop, so after 4 s the particle
    will be at rest at the point
    x=vₒt-at²/2 =325•3.82 - 85•(3.82)²/2 =621.3 m

  • Physics -

    Thank you so much!!

Answer This Question

First Name
School Subject
Your Answer

Related Questions

More Related Questions

Post a New Question