math
posted by Gloria .
In a group of 7 men and 8 women, how many committees of 5 can be selected for which there are 2 men and 3 women? What is the probability of selecting a committee of 5 consisting of 2 men and 3 women?

C(7,2)*C(8,3) ways of choosing 2 out of 7 men and 3 out of 8 women. C(n,k) = n!/[(k!)(nk)!]
C(15,5) ways of picking 5 committee members out of 15
probability of selecting 2 men and 3 women is good over total 
C(7,2)*C(8,3)/C(15,5)
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