If (x+y)^2=168 and xy =4, then x^2 + y^2=?

(x+y)^2 = 168

x^2 + 2xy + y^2 = 168
Replace xy with 4:
x^2 + 2*4 + y^2 = 168
x^2 + y^2 = 168 - 8 = 160.

Well, this problem looks like a puzzle where we have to find the value of x^2 + y^2. Let me try my hand at solving it while keeping things light-hearted!

So, first, let's expand (x+y)^2 = 168. That gives us x^2 + 2xy + y^2 = 168.

Since we know that xy = 4, we can substitute it back into the equation and simplify it a bit:

x^2 + 2(4) + y^2 = 168.

Now, we just need to find the value of x^2 + y^2.

Let's subtract 8 from both sides:

x^2 + y^2 = 168 - 8.

And voila! We have the solution. But, wait, before we reveal the final answer - let me entertain you a bit:

Why was the math textbook feeling sad?

Because it had too many problems!

Alright, back to the solution.

168 - 8 gives us 160. So, x^2 + y^2 = 160.

There you have it! x^2 + y^2 equals 160. I hope that puts a smile on your face, even if math doesn't always do the trick!

To solve the given equations, we can start by expanding the square of the sum of x and y.

(x+y)^2 = 168

Expanding this equation, we get:

x^2 + 2xy + y^2 = 168

We are also given that xy = 4. Substituting this value into the expanded equation, we have:

x^2 + 2(4) + y^2 = 168

Simplifying further:

x^2 + 8 + y^2 = 168

Now, to determine the value of x^2 + y^2, we need to isolate that term. We can do this by subtracting 8 from both sides:

x^2 + y^2 = 168 - 8

x^2 + y^2 = 160

Therefore, x^2 + y^2 is equal to 160.

To find the value of x^2 + y^2, we need to first expand the expression (x + y)^2.

(x + y)^2 can be written as (x + y)(x + y) using the formula for the square of a binomial.

Expanding this expression, we get:
(x + y)(x + y) = x(x + y) + y(x + y)
= x^2 + xy + yx + y^2
= x^2 + 2xy + y^2

We are given that (x + y)^2 = 168 and xy = 4. So, we can substitute these values into the expanded expression:

168 = x^2 + 2xy + y^2 (Substituting (x + y)^2 = 168)
168 = x^2 + 2(4) + y^2 (Substituting xy = 4)
168 = x^2 + 8 + y^2

Now, we need to isolate x^2 + y^2 on one side of the equation. Subtracting 8 from both sides:

168 - 8 = x^2 + y^2
160 = x^2 + y^2

Therefore, x^2 + y^2 = 160.