a motorisrt accelerates their car to 36m/s before realising they are over the speed limit and decelerates to 32m/s. calculate the distance traveled
distance=avgspeed*time
avgspeed=34m/s
time?
AT 36M/S FOR 4 SECS THEN DECLERATES TO 32M/S FOR 6 SECS. CALCULATE THE DISTANCE
See also response at:
http://www.jiskha.com/display.cgi?id=1339176192
To calculate the distance traveled by the motorist, we can use the formula:
Distance = (Initial Velocity + Final Velocity) / 2 * Time
First, we need to determine the time it took for the motorist to decelerate. Since we don't have any information about the time, we need to make an assumption that the deceleration happens over a short time interval.
Let's assume that the deceleration occurs instantly, which means the time taken is negligible.
Now, we can calculate the distance traveled:
Distance = (36 m/s + 32 m/s) / 2 * 0
Distance = (68 m/s) / 2 * 0
Distance = 68 m/s * 0
Distance = 0
According to this calculation, the distance traveled by the motorist is 0 meters. However, please note that this assumes instant deceleration, which is not realistic. In reality, the motorist would take some distance to slow down to the final velocity.