the mass of the crucible is 19.73 g fill the crucible with CuSO4 which was 26.44 g Heat the crucible until the water is released it weighed 23.40 g So now, how many moles of water is removed? The number of moles of CuSO4 that after dissolution rest? determine the number of H2O molecules, namely x, that is bound in CuSO4? set the equation for the decomposition reaction? find the correct value of x at. Calculate the percentage? is the hydration of CuSO4 exo-or endothermic?
So you want someone to do all of this? Show what you know to do and explain what you don't understand about the rest of the problem.
To answer your questions, let's go step by step:
1. How many moles of water are removed?
To determine the moles of water, we need to calculate the difference in mass before and after heating the crucible. The initial mass of the crucible, including the CuSO4, was 26.44 g, and after heating, it weighed 23.40 g. The difference in mass is due to the water being released. Therefore, the mass of water removed is:
Mass of water removed = Initial mass - Final mass
Mass of water removed = 26.44 g - 23.40 g = 3.04 g
Next, we need to convert the mass of water removed to moles. To do this, we use the molar mass of water, which is approximately 18.015 g/mol. Therefore, the number of moles of water removed can be calculated as follows:
Moles of water removed = Mass of water removed / Molar mass of water
Moles of water removed = 3.04 g / 18.015 g/mol ≈ 0.169 mol
2. The number of moles of CuSO4 after dissolution.
The mass of the crucible containing CuSO4 is 26.44g. To find the number of moles of CuSO4, we need to divide the mass by the molar mass of CuSO4. The molar mass of CuSO4 is the sum of the atomic masses of copper, sulfur, and four oxygen atoms:
Molar mass of CuSO4 = (atomic mass of Cu) + (atomic mass of S) + 4*(atomic mass of O)
Molar mass of CuSO4 = 63.55 g/mol + 32.07 g/mol + 4*(16.00 g/mol)
Molar mass of CuSO4 ≈ 159.61 g/mol
Now we can find the moles of CuSO4:
Moles of CuSO4 = Mass of CuSO4 / Molar mass of CuSO4
Moles of CuSO4 = 26.44 g / 159.61 g/mol ≈ 0.165 mol
3. The number of H2O molecules (x) bound in CuSO4.
In CuSO4, there are five water molecules bonded to one CuSO4 molecule. This is known as a pentahydrate compound. Therefore, the number of water molecules (x) bound in CuSO4 is 5.
4. The equation for the decomposition reaction.
The decomposition reaction for CuSO4 can be represented as:
CuSO4 · 5H2O(s) → CuSO4(s) + 5H2O(g)
5. Calculating the percentage.
To calculate the percentage, we need to divide the mass of water removed by the initial mass of CuSO4 in the crucible, then multiply by 100.
Percentage = (Mass of water removed / Initial mass of CuSO4) * 100
Percentage = (3.04 g / 26.44 g) * 100 ≈ 11.51%
6. Is the hydration of CuSO4 exothermic or endothermic?
The dehydration of CuSO4 is an endothermic process because heat is required to break the bonds between the water molecules and the CuSO4 compound. The energy is absorbed during the reaction, resulting in the release of water in its gaseous state.
I hope this helps! Let me know if you have any further questions.