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posted by JASLEEN .
alpha beta gamma are zeros of cubic polynomial x^312x^2+44x+c. if alpha beta gamma are in Ap find the value of c class 10

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jaya
(xalpha) (xbeta)(xgama) = x^3  12 x^2 + 44x+c. So x^3  x^2 (alpha+beta+gama)+ a(alphabeta+betagamma+gamma alpha)=alpha beta gama = x^3  12 x^2+44x+c, then alpha+beta+gama = 12.
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